mod-dev-talk Monday 1 November 2021

53 messages6 people

kalucky0Team11:53
I'm implementing Brainfuck
K
kalucky0Team12:02
- 🧠1
- 🍆1
sunsette12:15
oh dear.
kalucky0Team13:05
that's easier
tz.list
World TimeBot13:06
● 01-Nov 06:06 PDT (UTC-0700): Jack Papel#8773 ● 01-Nov 08:06 CDT (UTC-0500): CDAGaming#3162, 24Chrome#1098, Azzy (azazelthedemonlord#2563) ● 01-Nov 09:06 EDT (UTC-0400): nailuj29#4234, sunsette#6429, Kyrptonaught#4239 ● 01-Nov 14:06 CET (UTC+0100): Reoseah#7934, kalucky0#9373, PrezesE#3529 ● 01-Nov 16:06 MSK (UTC+0300): SweepSwap#2511 ● 02-Nov 00:06 AEDT (UTC+1100): Solly#0001
kalucky0Team13:07
@gudenau what's your timezone
i need you
Jack PapelTeam13:13
Should be the same as Azzy's iirc
kalucky0Team13:18
great
I will not sleep today
AzzyypaarasTeam17:17
Replying tokalucky0I will not sleep today
(he did sleep)
(sleepyhead)
(big zs)
kalucky0Team17:17
It's 18:17
I'm not asleep
Jack PapelTeam18:07
zzzz mimimimimi
kalucky0Team18:12

kalucky0Team19:01

Which behaviour is better?

 > $a=eval 4+4
 > $a
 eval 4+4

> $a=eval 4+4
> $a
8

Jack PapelTeam19:06
The second, I believe
The first one should need quotes imo
kalucky0Team19:26
I need to allow variable reassignment
Maybe loops
Jack PapelTeam19:35
This might be a dumb idea but what if $a = eval 4+4 stored not 8, but the operation eval 4+4. So like if it was $a = eval 2+$b and b changed, it'd be different. Ik it's not typical terminal stuff but it might be cool
kalucky0Team19:36
Replying toJack PapelThis might be a dumb idea but what if $a = eval 4+4 stored not 8, but the operation eval…
that what I was asking about
if running $a should evaluate or just return the contents
but currently evaluating breaks variable assignement
fuck that's complicated
but
I fucking love Copilot
kalucky0Team19:53
and it works perfectly
kalucky0Team20:02
nailuj22:56
Replying tokalucky0Which behaviour is better? > $a=eval 4+4 > $a eval 4+4 or > $a=eval 4+4 > $a 8
You're making a programming language
?
Practical or esoteric
kalucky0Team22:57
I'm making a shell
An OS
But
kalucky0Team23:04
somebody help(edited)
Jack PapelTeam23:08
Another problem: $a = eval $b + 1 $b = eval $a + 1 Leads to infinite recursion
kalucky0Team23:12
Replying tokalucky0an attachment
That's compilation error
AzzyypaarasTeam23:20
Replying toJack PapelAnother problem: $a = eval $b + 1 $b = eval $a + 1 Leads to infinite recursion
Shouldn't that just not compile... at all?
$a is referencing a variable that has not yet been declared
Jack PapelTeam23:21
Oh yeah good point
$a = 1 $b = eval $a + 1 $a = eval $b + 1
That should fix it
kalucky0Team23:24
Replying toAzzyypaarasShouldn't that just not compile... at all?
It's interpreted at runtime It may just cause kernel panic
AzzyypaarasTeam23:25
Jack PapelTeam23:30
Oh, just got accepted for testing GitHub Copilot